4(y-3)=5(y+1)-2y

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Solution for 4(y-3)=5(y+1)-2y equation: 



4(y-3)=5(y+1)-2y

We move all terms to the left:

4(y-3)-(5(y+1)-2y)=0

We multiply parentheses

4y-(5(y+1)-2y)-12=0



We calculate terms in parentheses: -(5(y+1)-2y), so:

5(y+1)-2y

We add all the numbers together, and all the variables

-2y+5(y+1)

We multiply parentheses

-2y+5y+5

We add all the numbers together, and all the variables

3y+5

Back to the equation:

-(3y+5)



We get rid of parentheses

4y-3y-5-12=0

We add all the numbers together, and all the variables

y-17=0

We move all terms containing y to the left, all other terms to the right

y=17

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