4(y-3)=3y-y+8

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Solution for 4(y-3)=3y-y+8 equation:



4(y-3)=3y-y+8
We move all terms to the left:
4(y-3)-(3y-y+8)=0
We add all the numbers together, and all the variables
4(y-3)-(2y+8)=0
We multiply parentheses
4y-(2y+8)-12=0
We get rid of parentheses
4y-2y-8-12=0
We add all the numbers together, and all the variables
2y-20=0
We move all terms containing y to the left, all other terms to the right
2y=20
y=20/2
y=10

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