4(y-3)=3(y+2)

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Solution for 4(y-3)=3(y+2) equation:


Simplifying
4(y + -3) = 3(y + 2)

Reorder the terms:
4(-3 + y) = 3(y + 2)
(-3 * 4 + y * 4) = 3(y + 2)
(-12 + 4y) = 3(y + 2)

Reorder the terms:
-12 + 4y = 3(2 + y)
-12 + 4y = (2 * 3 + y * 3)
-12 + 4y = (6 + 3y)

Solving
-12 + 4y = 6 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-12 + 4y + -3y = 6 + 3y + -3y

Combine like terms: 4y + -3y = 1y
-12 + 1y = 6 + 3y + -3y

Combine like terms: 3y + -3y = 0
-12 + 1y = 6 + 0
-12 + 1y = 6

Add '12' to each side of the equation.
-12 + 12 + 1y = 6 + 12

Combine like terms: -12 + 12 = 0
0 + 1y = 6 + 12
1y = 6 + 12

Combine like terms: 6 + 12 = 18
1y = 18

Divide each side by '1'.
y = 18

Simplifying
y = 18

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