4(y-3)=2(2y-5)-2

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Solution for 4(y-3)=2(2y-5)-2 equation: 



4(y-3)=2(2y-5)-2

We move all terms to the left:

4(y-3)-(2(2y-5)-2)=0

We multiply parentheses

4y-(2(2y-5)-2)-12=0



We calculate terms in parentheses: -(2(2y-5)-2), so:

2(2y-5)-2

We multiply parentheses

4y-10-2

We add all the numbers together, and all the variables

4y-12

Back to the equation:

-(4y-12)



We get rid of parentheses

4y-4y+12-12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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