4(y-3)-y=3(y+4)

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Solution for 4(y-3)-y=3(y+4) equation: 


Simplifying
4(y + -3) + -1y = 3(y + 4)

Reorder the terms:
4(-3 + y) + -1y = 3(y + 4)
(-3 * 4 + y * 4) + -1y = 3(y + 4)
(-12 + 4y) + -1y = 3(y + 4)

Combine like terms: 4y + -1y = 3y
-12 + 3y = 3(y + 4)

Reorder the terms:
-12 + 3y = 3(4 + y)
-12 + 3y = (4 * 3 + y * 3)
-12 + 3y = (12 + 3y)

Add '-3y' to each side of the equation.
-12 + 3y + -3y = 12 + 3y + -3y

Combine like terms: 3y + -3y = 0
-12 + 0 = 12 + 3y + -3y
-12 = 12 + 3y + -3y

Combine like terms: 3y + -3y = 0
-12 = 12 + 0
-12 = 12

Solving
-12 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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