4(y-3)-3(y-4)=12

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Solution for 4(y-3)-3(y-4)=12 equation: 



4(y-3)-3(y-4)=12

We move all terms to the left:

4(y-3)-3(y-4)-(12)=0

We multiply parentheses

4y-3y-12+12-12=0

We add all the numbers together, and all the variables

y-12=0

We move all terms containing y to the left, all other terms to the right

y=12

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