4(y-3)-(3y-5)=7

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Solution for 4(y-3)-(3y-5)=7 equation:



4(y-3)-(3y-5)=7
We move all terms to the left:
4(y-3)-(3y-5)-(7)=0
We multiply parentheses
4y-(3y-5)-12-7=0
We get rid of parentheses
4y-3y+5-12-7=0
We add all the numbers together, and all the variables
y-14=0
We move all terms containing y to the left, all other terms to the right
y=14

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