4(y-3)+12=64

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Solution for 4(y-3)+12=64 equation: 


Simplifying
4(y + -3) + 12 = 64

Reorder the terms:
4(-3 + y) + 12 = 64
(-3 * 4 + y * 4) + 12 = 64
(-12 + 4y) + 12 = 64

Reorder the terms:
-12 + 12 + 4y = 64

Combine like terms: -12 + 12 = 0
0 + 4y = 64
4y = 64

Solving
4y = 64

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '4'.
y = 16

Simplifying
y = 16

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