4(y-2)=6y+2-2(-3y-2)

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Solution for 4(y-2)=6y+2-2(-3y-2) equation: 



4(y-2)=6y+2-2(-3y-2)

We move all terms to the left:

4(y-2)-(6y+2-2(-3y-2))=0

We multiply parentheses

4y-(6y+2-2(-3y-2))-8=0



We calculate terms in parentheses: -(6y+2-2(-3y-2)), so:

6y+2-2(-3y-2)

determiningTheFunctionDomain
6y-2(-3y-2)+2

We multiply parentheses

6y+6y+4+2

We add all the numbers together, and all the variables

12y+6

Back to the equation:

-(12y+6)



We get rid of parentheses

4y-12y-6-8=0

We add all the numbers together, and all the variables

-8y-14=0

We move all terms containing y to the left, all other terms to the right

-8y=14

y=14/-8

y=-1+3/4

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