4(y-2)=2y-28

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Solution for 4(y-2)=2y-28 equation:



4(y-2)=2y-28
We move all terms to the left:
4(y-2)-(2y-28)=0
We multiply parentheses
4y-(2y-28)-8=0
We get rid of parentheses
4y-2y+28-8=0
We add all the numbers together, and all the variables
2y+20=0
We move all terms containing y to the left, all other terms to the right
2y=-20
y=-20/2
y=-10

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