4(y-2)=2y+28

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Solution for 4(y-2)=2y+28 equation: 



4(y-2)=2y+28

We move all terms to the left:

4(y-2)-(2y+28)=0

We multiply parentheses

4y-(2y+28)-8=0

We get rid of parentheses

4y-2y-28-8=0

We add all the numbers together, and all the variables

2y-36=0

We move all terms containing y to the left, all other terms to the right

2y=36

y=36/2

y=18

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