4(y-2)-3=-3(-9y+7)-5y

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Solution for 4(y-2)-3=-3(-9y+7)-5y equation:



4(y-2)-3=-3(-9y+7)-5y
We move all terms to the left:
4(y-2)-3-(-3(-9y+7)-5y)=0
We multiply parentheses
4y-(-3(-9y+7)-5y)-8-3=0
We calculate terms in parentheses: -(-3(-9y+7)-5y), so:
-3(-9y+7)-5y
We add all the numbers together, and all the variables
-5y-3(-9y+7)
We multiply parentheses
-5y+27y-21
We add all the numbers together, and all the variables
22y-21
Back to the equation:
-(22y-21)
We add all the numbers together, and all the variables
4y-(22y-21)-11=0
We get rid of parentheses
4y-22y+21-11=0
We add all the numbers together, and all the variables
-18y+10=0
We move all terms containing y to the left, all other terms to the right
-18y=-10
y=-10/-18
y=5/9

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