4(y-2)-2=2(y+1)-5

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Solution for 4(y-2)-2=2(y+1)-5 equation: 



4(y-2)-2=2(y+1)-5

We move all terms to the left:

4(y-2)-2-(2(y+1)-5)=0

We multiply parentheses

4y-(2(y+1)-5)-8-2=0



We calculate terms in parentheses: -(2(y+1)-5), so:

2(y+1)-5

We multiply parentheses

2y+2-5

We add all the numbers together, and all the variables

2y-3

Back to the equation:

-(2y-3)



We add all the numbers together, and all the variables

4y-(2y-3)-10=0

We get rid of parentheses

4y-2y+3-10=0

We add all the numbers together, and all the variables

2y-7=0

We move all terms containing y to the left, all other terms to the right

2y=7

y=7/2

y=3+1/2

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