4(y-2)+6y=7(y-8)-3(10-y)

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Solution for 4(y-2)+6y=7(y-8)-3(10-y) equation: 



4(y-2)+6y=7(y-8)-3(10-y)

We move all terms to the left:

4(y-2)+6y-(7(y-8)-3(10-y))=0

We add all the numbers together, and all the variables

4(y-2)+6y-(7(y-8)-3(-1y+10))=0

We add all the numbers together, and all the variables

6y+4(y-2)-(7(y-8)-3(-1y+10))=0

We multiply parentheses

6y+4y-(7(y-8)-3(-1y+10))-8=0



We calculate terms in parentheses: -(7(y-8)-3(-1y+10)), so:

7(y-8)-3(-1y+10)

We multiply parentheses

7y+3y-56-30

We add all the numbers together, and all the variables

10y-86

Back to the equation:

-(10y-86)



We add all the numbers together, and all the variables

10y-(10y-86)-8=0

We get rid of parentheses

10y-10y+86-8=0

We add all the numbers together, and all the variables

78!=0

There is no solution for this equation

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