4(y-2)+10=2(y+3)+2y

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Solution for 4(y-2)+10=2(y+3)+2y equation: 



4(y-2)+10=2(y+3)+2y

We move all terms to the left:

4(y-2)+10-(2(y+3)+2y)=0

We multiply parentheses

4y-(2(y+3)+2y)-8+10=0



We calculate terms in parentheses: -(2(y+3)+2y), so:

2(y+3)+2y

We add all the numbers together, and all the variables

2y+2(y+3)

We multiply parentheses

2y+2y+6

We add all the numbers together, and all the variables

4y+6

Back to the equation:

-(4y+6)



We add all the numbers together, and all the variables

4y-(4y+6)+2=0

We get rid of parentheses

4y-4y-6+2=0

We add all the numbers together, and all the variables

-4!=0

There is no solution for this equation

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