4(y-1)=2y+3

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Solution for 4(y-1)=2y+3 equation: 



4(y-1)=2y+3

We move all terms to the left:

4(y-1)-(2y+3)=0

We multiply parentheses

4y-(2y+3)-4=0

We get rid of parentheses

4y-2y-3-4=0

We add all the numbers together, and all the variables

2y-7=0

We move all terms containing y to the left, all other terms to the right

2y=7

y=7/2

y=3+1/2

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