4(y-1)+7=+5(2y-3)

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Solution for 4(y-1)+7=+5(2y-3) equation: 



4(y-1)+7=+5(2y-3)

We move all terms to the left:

4(y-1)+7-(+5(2y-3))=0

We multiply parentheses

4y-(+5(2y-3))-4+7=0



We calculate terms in parentheses: -(+5(2y-3)), so:

+5(2y-3)

determiningTheFunctionDomain
5(2y-3)

We multiply parentheses

10y-15

Back to the equation:

-(10y-15)



We add all the numbers together, and all the variables

4y-(10y-15)+3=0

We get rid of parentheses

4y-10y+15+3=0

We add all the numbers together, and all the variables

-6y+18=0

We move all terms containing y to the left, all other terms to the right

-6y=-18

y=-18/-6

y=+3

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