4(y+6)=-5(3y-2)+3y

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Solution for 4(y+6)=-5(3y-2)+3y equation: 



4(y+6)=-5(3y-2)+3y

We move all terms to the left:

4(y+6)-(-5(3y-2)+3y)=0

We multiply parentheses

4y-(-5(3y-2)+3y)+24=0



We calculate terms in parentheses: -(-5(3y-2)+3y), so:

-5(3y-2)+3y

We add all the numbers together, and all the variables

3y-5(3y-2)

We multiply parentheses

3y-15y+10

We add all the numbers together, and all the variables

-12y+10

Back to the equation:

-(-12y+10)



We get rid of parentheses

4y+12y-10+24=0

We add all the numbers together, and all the variables

16y+14=0

We move all terms containing y to the left, all other terms to the right

16y=-14

y=-14/16

y=-7/8

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