4(y+4)=4(y+4)=32

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Solution for 4(y+4)=4(y+4)=32 equation: 



4(y+4)=4(y+4)=32

We move all terms to the left:

4(y+4)-(4(y+4))=0

We multiply parentheses

4y-(4(y+4))+16=0



We calculate terms in parentheses: -(4(y+4)), so:

4(y+4)

We multiply parentheses

4y+16

Back to the equation:

-(4y+16)



We get rid of parentheses

4y-4y-16+16=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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