4(y+3)=3(y-5)+y

Solution for 4(y+3)=3(y-5)+y equation:

4(y+3)=3(y-5)+y

We move all terms to the left:

4(y+3)-(3(y-5)+y)=0

We multiply parentheses

4y-(3(y-5)+y)+12=0


We calculate terms in parentheses: -(3(y-5)+y), so:

3(y-5)+y

We add all the numbers together, and all the variables

y+3(y-5)

We multiply parentheses

y+3y-15

We add all the numbers together, and all the variables

4y-15

Back to the equation:

-(4y-15)


We get rid of parentheses

4y-4y+15+12=0

We add all the numbers together, and all the variables

27!=0

There is no solution for this equation