4(y+3)=3(y-2)

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Solution for 4(y+3)=3(y-2) equation:


Simplifying
4(y + 3) = 3(y + -2)

Reorder the terms:
4(3 + y) = 3(y + -2)
(3 * 4 + y * 4) = 3(y + -2)
(12 + 4y) = 3(y + -2)

Reorder the terms:
12 + 4y = 3(-2 + y)
12 + 4y = (-2 * 3 + y * 3)
12 + 4y = (-6 + 3y)

Solving
12 + 4y = -6 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
12 + 4y + -3y = -6 + 3y + -3y

Combine like terms: 4y + -3y = 1y
12 + 1y = -6 + 3y + -3y

Combine like terms: 3y + -3y = 0
12 + 1y = -6 + 0
12 + 1y = -6

Add '-12' to each side of the equation.
12 + -12 + 1y = -6 + -12

Combine like terms: 12 + -12 = 0
0 + 1y = -6 + -12
1y = -6 + -12

Combine like terms: -6 + -12 = -18
1y = -18

Divide each side by '1'.
y = -18

Simplifying
y = -18

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