4(y+3)=2(3y+10)

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Solution for 4(y+3)=2(3y+10) equation:


Simplifying
4(y + 3) = 2(3y + 10)

Reorder the terms:
4(3 + y) = 2(3y + 10)
(3 * 4 + y * 4) = 2(3y + 10)
(12 + 4y) = 2(3y + 10)

Reorder the terms:
12 + 4y = 2(10 + 3y)
12 + 4y = (10 * 2 + 3y * 2)
12 + 4y = (20 + 6y)

Solving
12 + 4y = 20 + 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
12 + 4y + -6y = 20 + 6y + -6y

Combine like terms: 4y + -6y = -2y
12 + -2y = 20 + 6y + -6y

Combine like terms: 6y + -6y = 0
12 + -2y = 20 + 0
12 + -2y = 20

Add '-12' to each side of the equation.
12 + -12 + -2y = 20 + -12

Combine like terms: 12 + -12 = 0
0 + -2y = 20 + -12
-2y = 20 + -12

Combine like terms: 20 + -12 = 8
-2y = 8

Divide each side by '-2'.
y = -4

Simplifying
y = -4

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