4(y+3)-6y=18

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Solution for 4(y+3)-6y=18 equation: 



4(y+3)-6y=18

We move all terms to the left:

4(y+3)-6y-(18)=0

We add all the numbers together, and all the variables

-6y+4(y+3)-18=0

We multiply parentheses

-6y+4y+12-18=0

We add all the numbers together, and all the variables

-2y-6=0

We move all terms containing y to the left, all other terms to the right

-2y=6

y=6/-2

y=-3

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