4(y+3)+2y-12=3(y+2)

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Solution for 4(y+3)+2y-12=3(y+2) equation: 



4(y+3)+2y-12=3(y+2)

We move all terms to the left:

4(y+3)+2y-12-(3(y+2))=0

We add all the numbers together, and all the variables

2y+4(y+3)-(3(y+2))-12=0

We multiply parentheses

2y+4y-(3(y+2))+12-12=0



We calculate terms in parentheses: -(3(y+2)), so:

3(y+2)

We multiply parentheses

3y+6

Back to the equation:

-(3y+6)



We add all the numbers together, and all the variables

6y-(3y+6)=0

We get rid of parentheses

6y-3y-6=0

We add all the numbers together, and all the variables

3y-6=0

We move all terms containing y to the left, all other terms to the right

3y=6

y=6/3

y=2

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