4(y+3)+1y=8

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Solution for 4(y+3)+1y=8 equation: 



4(y+3)+1y=8

We move all terms to the left:

4(y+3)+1y-(8)=0

We add all the numbers together, and all the variables

y+4(y+3)-8=0

We multiply parentheses

y+4y+12-8=0

We add all the numbers together, and all the variables

5y+4=0

We move all terms containing y to the left, all other terms to the right

5y=-4

y=-4/5

y=-4/5

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