4(y+2)-y=2(y+-1)+9

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Solution for 4(y+2)-y=2(y+-1)+9 equation: 



4(y+2)-y=2(y+-1)+9

We move all terms to the left:

4(y+2)-y-(2(y+-1)+9)=0

We add all the numbers together, and all the variables

4(y+2)-y-(2(y-1)+9)=0

We add all the numbers together, and all the variables

-1y+4(y+2)-(2(y-1)+9)=0

We multiply parentheses

-1y+4y-(2(y-1)+9)+8=0



We calculate terms in parentheses: -(2(y-1)+9), so:

2(y-1)+9

We multiply parentheses

2y-2+9

We add all the numbers together, and all the variables

2y+7

Back to the equation:

-(2y+7)



We add all the numbers together, and all the variables

3y-(2y+7)+8=0

We get rid of parentheses

3y-2y-7+8=0

We add all the numbers together, and all the variables

y+1=0

We move all terms containing y to the left, all other terms to the right

y=-1

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