4(y+2)+y=4(y-1)+10

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Solution for 4(y+2)+y=4(y-1)+10 equation: 



4(y+2)+y=4(y-1)+10

We move all terms to the left:

4(y+2)+y-(4(y-1)+10)=0

We add all the numbers together, and all the variables

y+4(y+2)-(4(y-1)+10)=0

We multiply parentheses

y+4y-(4(y-1)+10)+8=0



We calculate terms in parentheses: -(4(y-1)+10), so:

4(y-1)+10

We multiply parentheses

4y-4+10

We add all the numbers together, and all the variables

4y+6

Back to the equation:

-(4y+6)



We add all the numbers together, and all the variables

5y-(4y+6)+8=0

We get rid of parentheses

5y-4y-6+8=0

We add all the numbers together, and all the variables

y+2=0

We move all terms containing y to the left, all other terms to the right

y=-2

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