4(y+2)+3y=-6

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Solution for 4(y+2)+3y=-6 equation: 



4(y+2)+3y=-6

We move all terms to the left:

4(y+2)+3y-(-6)=0

We add all the numbers together, and all the variables

3y+4(y+2)+6=0

We multiply parentheses

3y+4y+8+6=0

We add all the numbers together, and all the variables

7y+14=0

We move all terms containing y to the left, all other terms to the right

7y=-14

y=-14/7

y=-2

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