4(y+2)+2(3y-y)=3(3y-1)

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Solution for 4(y+2)+2(3y-y)=3(3y-1) equation: 



4(y+2)+2(3y-y)=3(3y-1)

We move all terms to the left:

4(y+2)+2(3y-y)-(3(3y-1))=0

We add all the numbers together, and all the variables

4(y+2)+2(+2y)-(3(3y-1))=0

We multiply parentheses

4y+4y-(3(3y-1))+8=0



We calculate terms in parentheses: -(3(3y-1)), so:

3(3y-1)

We multiply parentheses

9y-3

Back to the equation:

-(9y-3)



We add all the numbers together, and all the variables

8y-(9y-3)+8=0

We get rid of parentheses

8y-9y+3+8=0

We add all the numbers together, and all the variables

-1y+11=0

We move all terms containing y to the left, all other terms to the right

-y=-11

y=-11/-1

y=+11

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