4(y+1)=7(y-1)

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Solution for 4(y+1)=7(y-1) equation: 



4(y+1)=7(y-1)

We move all terms to the left:

4(y+1)-(7(y-1))=0

We multiply parentheses

4y-(7(y-1))+4=0



We calculate terms in parentheses: -(7(y-1)), so:

7(y-1)

We multiply parentheses

7y-7

Back to the equation:

-(7y-7)



We get rid of parentheses

4y-7y+7+4=0

We add all the numbers together, and all the variables

-3y+11=0

We move all terms containing y to the left, all other terms to the right

-3y=-11

y=-11/-3

y=3+2/3

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