4(y+1)=3(y+2)

Solution for 4(y+1)=3(y+2) equation:

Simplifying
4(y + 1) = 3(y + 2)

Reorder the terms:
4(1 + y) = 3(y + 2)
(1 * 4 + y * 4) = 3(y + 2)
(4 + 4y) = 3(y + 2)

Reorder the terms:
4 + 4y = 3(2 + y)
4 + 4y = (2 * 3 + y * 3)
4 + 4y = (6 + 3y)

Solving
4 + 4y = 6 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
4 + 4y + -3y = 6 + 3y + -3y

Combine like terms: 4y + -3y = 1y
4 + 1y = 6 + 3y + -3y

Combine like terms: 3y + -3y = 0
4 + 1y = 6 + 0
4 + 1y = 6

Add '-4' to each side of the equation.
4 + -4 + 1y = 6 + -4

Combine like terms: 4 + -4 = 0
0 + 1y = 6 + -4
1y = 6 + -4

Combine like terms: 6 + -4 = 2
1y = 2

Divide each side by '1'.
y = 2

Simplifying
y = 2