4(y+1)-y=(y-1)+3

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Solution for 4(y+1)-y=(y-1)+3 equation: 



4(y+1)-y=(y-1)+3

We move all terms to the left:

4(y+1)-y-((y-1)+3)=0

We add all the numbers together, and all the variables

-1y+4(y+1)-((y-1)+3)=0

We multiply parentheses

-1y+4y-((y-1)+3)+4=0



We calculate terms in parentheses: -((y-1)+3), so:

(y-1)+3

We get rid of parentheses

y-1+3

We add all the numbers together, and all the variables

y+2

Back to the equation:

-(y+2)



We add all the numbers together, and all the variables

3y-(y+2)+4=0

We get rid of parentheses

3y-y-2+4=0

We add all the numbers together, and all the variables

2y+2=0

We move all terms containing y to the left, all other terms to the right

2y=-2

y=-2/2

y=-1

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