4(y+1)-6(y-2)=10y+16-12y

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Solution for 4(y+1)-6(y-2)=10y+16-12y equation:


Simplifying
4(y + 1) + -6(y + -2) = 10y + 16 + -12y

Reorder the terms:
4(1 + y) + -6(y + -2) = 10y + 16 + -12y
(1 * 4 + y * 4) + -6(y + -2) = 10y + 16 + -12y
(4 + 4y) + -6(y + -2) = 10y + 16 + -12y

Reorder the terms:
4 + 4y + -6(-2 + y) = 10y + 16 + -12y
4 + 4y + (-2 * -6 + y * -6) = 10y + 16 + -12y
4 + 4y + (12 + -6y) = 10y + 16 + -12y

Reorder the terms:
4 + 12 + 4y + -6y = 10y + 16 + -12y

Combine like terms: 4 + 12 = 16
16 + 4y + -6y = 10y + 16 + -12y

Combine like terms: 4y + -6y = -2y
16 + -2y = 10y + 16 + -12y

Reorder the terms:
16 + -2y = 16 + 10y + -12y

Combine like terms: 10y + -12y = -2y
16 + -2y = 16 + -2y

Add '-16' to each side of the equation.
16 + -16 + -2y = 16 + -16 + -2y

Combine like terms: 16 + -16 = 0
0 + -2y = 16 + -16 + -2y
-2y = 16 + -16 + -2y

Combine like terms: 16 + -16 = 0
-2y = 0 + -2y
-2y = -2y

Add '2y' to each side of the equation.
-2y + 2y = -2y + 2y

Combine like terms: -2y + 2y = 0
0 = -2y + 2y

Combine like terms: -2y + 2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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