4(y+1)+y=(3y-2)+2

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Solution for 4(y+1)+y=(3y-2)+2 equation: 



4(y+1)+y=(3y-2)+2

We move all terms to the left:

4(y+1)+y-((3y-2)+2)=0

We add all the numbers together, and all the variables

y+4(y+1)-((3y-2)+2)=0

We multiply parentheses

y+4y-((3y-2)+2)+4=0



We calculate terms in parentheses: -((3y-2)+2), so:

(3y-2)+2

We get rid of parentheses

3y-2+2

We add all the numbers together, and all the variables

3y

Back to the equation:

-(3y)



We add all the numbers together, and all the variables

2y+4=0

We move all terms containing y to the left, all other terms to the right

2y=-4

y=-4/2

y=-2

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