4(y+1)+4=5(y-1)+9

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Solution for 4(y+1)+4=5(y-1)+9 equation: 



4(y+1)+4=5(y-1)+9

We move all terms to the left:

4(y+1)+4-(5(y-1)+9)=0

We multiply parentheses

4y-(5(y-1)+9)+4+4=0



We calculate terms in parentheses: -(5(y-1)+9), so:

5(y-1)+9

We multiply parentheses

5y-5+9

We add all the numbers together, and all the variables

5y+4

Back to the equation:

-(5y+4)



We add all the numbers together, and all the variables

4y-(5y+4)+8=0

We get rid of parentheses

4y-5y-4+8=0

We add all the numbers together, and all the variables

-1y+4=0

We move all terms containing y to the left, all other terms to the right

-y=-4

y=-4/-1

y=+4

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