4(y+1)+3y-1=7y+1

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Solution for 4(y+1)+3y-1=7y+1 equation: 



4(y+1)+3y-1=7y+1

We move all terms to the left:

4(y+1)+3y-1-(7y+1)=0

We add all the numbers together, and all the variables

3y+4(y+1)-(7y+1)-1=0

We multiply parentheses

3y+4y-(7y+1)+4-1=0

We get rid of parentheses

3y+4y-7y-1+4-1=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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