4(y+(-5))=5(y+3)+(-9)

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Solution for 4(y+(-5))=5(y+3)+(-9) equation: 



4(y+(-5))=5(y+3)+(-9)

We move all terms to the left:

4(y+(-5))-(5(y+3)+(-9))=0



We calculate terms in parentheses: -(5(y+3)+(-9)), so:

5(y+3)+(-9)

We add all the numbers together, and all the variables

5(y+3)-9

We multiply parentheses

5y+15-9

We add all the numbers together, and all the variables

5y+6

Back to the equation:

-(5y+6)



We get rid of parentheses

4(y+(-5))-5y-6=0

We add all the numbers together, and all the variables

-5y+4(y+(-5))-6=0

We move all terms containing y to the left, all other terms to the right

-5y+4(y+(-5))=6

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