4(x2+x)=(2x+1)(2x-1)

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Solution for 4(x2+x)=(2x+1)(2x-1) equation: 



4(x2+x)=(2x+1)(2x-1)

We move all terms to the left:

4(x2+x)-((2x+1)(2x-1))=0

We add all the numbers together, and all the variables

4(+x^2+x)-((2x+1)(2x-1))=0

We use the square of the difference formula

4(+x^2+x)+4x^2+1=0

We multiply parentheses

4x^2+4x^2+4x+1=0

We add all the numbers together, and all the variables

8x^2+4x+1=0

a = 8; b = 4; c = +1;
Δ = b2-4ac
Δ = 42-4·8·1
Δ = -16
Delta is less than zero, so there is no solution for the equation

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