4(x-8)+7x=67+2x

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Solution for 4(x-8)+7x=67+2x equation:



4(x-8)+7x=67+2x
We move all terms to the left:
4(x-8)+7x-(67+2x)=0
We add all the numbers together, and all the variables
4(x-8)+7x-(2x+67)=0
We add all the numbers together, and all the variables
7x+4(x-8)-(2x+67)=0
We multiply parentheses
7x+4x-(2x+67)-32=0
We get rid of parentheses
7x+4x-2x-67-32=0
We add all the numbers together, and all the variables
9x-99=0
We move all terms containing x to the left, all other terms to the right
9x=99
x=99/9
x=11

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