4(x-8)+20=2(x-5)

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Solution for 4(x-8)+20=2(x-5) equation:


Simplifying
4(x + -8) + 20 = 2(x + -5)

Reorder the terms:
4(-8 + x) + 20 = 2(x + -5)
(-8 * 4 + x * 4) + 20 = 2(x + -5)
(-32 + 4x) + 20 = 2(x + -5)

Reorder the terms:
-32 + 20 + 4x = 2(x + -5)

Combine like terms: -32 + 20 = -12
-12 + 4x = 2(x + -5)

Reorder the terms:
-12 + 4x = 2(-5 + x)
-12 + 4x = (-5 * 2 + x * 2)
-12 + 4x = (-10 + 2x)

Solving
-12 + 4x = -10 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
-12 + 4x + -2x = -10 + 2x + -2x

Combine like terms: 4x + -2x = 2x
-12 + 2x = -10 + 2x + -2x

Combine like terms: 2x + -2x = 0
-12 + 2x = -10 + 0
-12 + 2x = -10

Add '12' to each side of the equation.
-12 + 12 + 2x = -10 + 12

Combine like terms: -12 + 12 = 0
0 + 2x = -10 + 12
2x = -10 + 12

Combine like terms: -10 + 12 = 2
2x = 2

Divide each side by '2'.
x = 1

Simplifying
x = 1

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