4(x-7)=4(x+2)-3-3x

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Solution for 4(x-7)=4(x+2)-3-3x equation: 



4(x-7)=4(x+2)-3-3x

We move all terms to the left:

4(x-7)-(4(x+2)-3-3x)=0

We multiply parentheses

4x-(4(x+2)-3-3x)-28=0



We calculate terms in parentheses: -(4(x+2)-3-3x), so:

4(x+2)-3-3x

determiningTheFunctionDomain
4(x+2)-3x-3

We add all the numbers together, and all the variables

-3x+4(x+2)-3

We multiply parentheses

-3x+4x+8-3

We add all the numbers together, and all the variables

x+5

Back to the equation:

-(x+5)



We get rid of parentheses

4x-x-5-28=0

We add all the numbers together, and all the variables

3x-33=0

We move all terms containing x to the left, all other terms to the right

3x=33

x=33/3

x=11

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