4(x-7)+3=2(10-x)

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Solution for 4(x-7)+3=2(10-x) equation: 



4(x-7)+3=2(10-x)

We move all terms to the left:

4(x-7)+3-(2(10-x))=0

We add all the numbers together, and all the variables

4(x-7)-(2(-1x+10))+3=0

We multiply parentheses

4x-(2(-1x+10))-28+3=0



We calculate terms in parentheses: -(2(-1x+10)), so:

2(-1x+10)

We multiply parentheses

-2x+20

Back to the equation:

-(-2x+20)



We add all the numbers together, and all the variables

4x-(-2x+20)-25=0

We get rid of parentheses

4x+2x-20-25=0

We add all the numbers together, and all the variables

6x-45=0

We move all terms containing x to the left, all other terms to the right

6x=45

x=45/6

x=7+1/2

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