4(x-6)+3x=9(x-2)+10

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Solution for 4(x-6)+3x=9(x-2)+10 equation: 



4(x-6)+3x=9(x-2)+10

We move all terms to the left:

4(x-6)+3x-(9(x-2)+10)=0

We add all the numbers together, and all the variables

3x+4(x-6)-(9(x-2)+10)=0

We multiply parentheses

3x+4x-(9(x-2)+10)-24=0



We calculate terms in parentheses: -(9(x-2)+10), so:

9(x-2)+10

We multiply parentheses

9x-18+10

We add all the numbers together, and all the variables

9x-8

Back to the equation:

-(9x-8)



We add all the numbers together, and all the variables

7x-(9x-8)-24=0

We get rid of parentheses

7x-9x+8-24=0

We add all the numbers together, and all the variables

-2x-16=0

We move all terms containing x to the left, all other terms to the right

-2x=16

x=16/-2

x=-8

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