4(x-5)=8x-(20+4x)

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Solution for 4(x-5)=8x-(20+4x) equation: 



4(x-5)=8x-(20+4x)

We move all terms to the left:

4(x-5)-(8x-(20+4x))=0

We add all the numbers together, and all the variables

4(x-5)-(8x-(4x+20))=0

We multiply parentheses

4x-(8x-(4x+20))-20=0



We calculate terms in parentheses: -(8x-(4x+20)), so:

8x-(4x+20)

We get rid of parentheses

8x-4x-20

We add all the numbers together, and all the variables

4x-20

Back to the equation:

-(4x-20)



We get rid of parentheses

4x-4x+20-20=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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