4(x-5)=2(x-8)+x

Solution for 4(x-5)=2(x-8)+x equation:

4(x-5)=2(x-8)+x

We move all terms to the left:

4(x-5)-(2(x-8)+x)=0

We multiply parentheses

4x-(2(x-8)+x)-20=0


We calculate terms in parentheses: -(2(x-8)+x), so:

2(x-8)+x

We add all the numbers together, and all the variables

x+2(x-8)

We multiply parentheses

x+2x-16

We add all the numbers together, and all the variables

3x-16

Back to the equation:

-(3x-16)


We get rid of parentheses

4x-3x+16-20=0

We add all the numbers together, and all the variables

x-4=0

We move all terms containing x to the left, all other terms to the right

x=4