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4(x-5)=2(-10+2x)
We move all terms to the left:
4(x-5)-(2(-10+2x))=0
We add all the numbers together, and all the variables
4(x-5)-(2(2x-10))=0
We multiply parentheses
4x-(2(2x-10))-20=0
We calculate terms in parentheses: -(2(2x-10)), so:We get rid of parentheses
2(2x-10)
We multiply parentheses
4x-20
Back to the equation:
-(4x-20)
4x-4x+20-20=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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