4(x-5)-5(x-4)=x+6-(x-2)

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Solution for 4(x-5)-5(x-4)=x+6-(x-2) equation: 



4(x-5)-5(x-4)=x+6-(x-2)

We move all terms to the left:

4(x-5)-5(x-4)-(x+6-(x-2))=0

We multiply parentheses

4x-5x-(x+6-(x-2))-20+20=0



We calculate terms in parentheses: -(x+6-(x-2)), so:

x+6-(x-2)

determiningTheFunctionDomain
x-(x-2)+6

We get rid of parentheses

x-x+2+6

We add all the numbers together, and all the variables

8

Back to the equation:

-(8)



We add all the numbers together, and all the variables

-1x-8=0

We move all terms containing x to the left, all other terms to the right

-x=8

x=8/-1

x=-8

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