4(x-5)-3(7+2x)+57=6(4x-x)+2(x-8)

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Solution for 4(x-5)-3(7+2x)+57=6(4x-x)+2(x-8) equation: 



4(x-5)-3(7+2x)+57=6(4x-x)+2(x-8)

We move all terms to the left:

4(x-5)-3(7+2x)+57-(6(4x-x)+2(x-8))=0

We add all the numbers together, and all the variables

4(x-5)-3(2x+7)-(6(+3x)+2(x-8))+57=0

We multiply parentheses

4x-6x-(6(+3x)+2(x-8))-20-21+57=0



We calculate terms in parentheses: -(6(+3x)+2(x-8)), so:

6(+3x)+2(x-8)

We multiply parentheses

18x+2x-16

We add all the numbers together, and all the variables

20x-16

Back to the equation:

-(20x-16)



We add all the numbers together, and all the variables

-2x-(20x-16)+16=0

We get rid of parentheses

-2x-20x+16+16=0

We add all the numbers together, and all the variables

-22x+32=0

We move all terms containing x to the left, all other terms to the right

-22x=-32

x=-32/-22

x=1+5/11

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