4(x-5)+6=3(x-4)+x-4

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Solution for 4(x-5)+6=3(x-4)+x-4 equation: 


Simplifying
4(x + -5) + 6 = 3(x + -4) + x + -4

Reorder the terms:
4(-5 + x) + 6 = 3(x + -4) + x + -4
(-5 * 4 + x * 4) + 6 = 3(x + -4) + x + -4
(-20 + 4x) + 6 = 3(x + -4) + x + -4

Reorder the terms:
-20 + 6 + 4x = 3(x + -4) + x + -4

Combine like terms: -20 + 6 = -14
-14 + 4x = 3(x + -4) + x + -4

Reorder the terms:
-14 + 4x = 3(-4 + x) + x + -4
-14 + 4x = (-4 * 3 + x * 3) + x + -4
-14 + 4x = (-12 + 3x) + x + -4

Reorder the terms:
-14 + 4x = -12 + -4 + 3x + x

Combine like terms: -12 + -4 = -16
-14 + 4x = -16 + 3x + x

Combine like terms: 3x + x = 4x
-14 + 4x = -16 + 4x

Add '-4x' to each side of the equation.
-14 + 4x + -4x = -16 + 4x + -4x

Combine like terms: 4x + -4x = 0
-14 + 0 = -16 + 4x + -4x
-14 = -16 + 4x + -4x

Combine like terms: 4x + -4x = 0
-14 = -16 + 0
-14 = -16

Solving
-14 = -16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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