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4(x-5)+3x=2(-3x+3)
We move all terms to the left:
4(x-5)+3x-(2(-3x+3))=0
We add all the numbers together, and all the variables
3x+4(x-5)-(2(-3x+3))=0
We multiply parentheses
3x+4x-(2(-3x+3))-20=0
We calculate terms in parentheses: -(2(-3x+3)), so:We add all the numbers together, and all the variables
2(-3x+3)
We multiply parentheses
-6x+6
Back to the equation:
-(-6x+6)
7x-(-6x+6)-20=0
We get rid of parentheses
7x+6x-6-20=0
We add all the numbers together, and all the variables
13x-26=0
We move all terms containing x to the left, all other terms to the right
13x=26
x=26/13
x=2
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